Math, asked by rahmatullahr375, 4 days ago

A farmer buys an ox for $7500. After one year he sells it at a loss of 15%. Find the selling price of the ox? ​

Answers

Answered by mayanknagdali122993
0

Answer:

Loss of 5%

∴Loss=

100

5

×44000=2200

Selling price of buffalo =Rs.44000−2200=Rs. 41800

Cost price of cow =Rs.18000

Profit of 10%

Hence,

profit=

100

10

×18000=1800

So, Price=18000+1800=Rs. 19800

Cost price of both cow and buffalo

=44000+18000=Rs. 62000

Selling price of both cow and buffalo

⇒Rs.(19800+41800)=Rs.61600

∴Loss=62000−61600=Rs.400

Answered by prachibarapatre
0

Answer:

The selling price of the ox will be $6375

Step-by-step explanation:

The cost price of the ox is given to  be $7500

It is given that it is sold at a loss of 15%

So, first we will find out 15% of $7500

loss = 15% of 7500

       = (15/100) × 7500

       = 1125

selling price = cost price - loss

                    = 7500 - 1125

                   = 6375

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