a farmer completes 2.5 rounds walking along the edge of a field in square shape of side 50 m. 1) the distance travelled is ___meter and displacement is ____meter
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1
Answer:
Given side of square =10m, thus perimeter P=40m
Time taken to cover the boundary of 40 m =40 s
Thus in 1 second, the farmer covers a distance of 1 m
Now distance covered by the farmer in 2 min 20 seconds = 1×140=140m
Now the total number of rotation the farmer makes to cover a distance of 140 meters =
perimeter
totaldistance
=3.5
At this point, the farmer is at a point say B from the origin O
Thus the displacement s=
10
2
+10
2
from Pythagoras theorem.
s=10
2
=14.14m
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Answer:
a farmer complete 2.5 rounds walking along the age of a field in square shape of side 50 m 1) the distance travelled is 500 meter and displacement is 70.71meter.
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