A farmer connects a pipe of internal diameter 20 cm from a canal into a cylinder tank in her field which is 10 cm in diametre and 2m deep. rate of flowing water=3 km/hr,find the time in which tank is filled.
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Rate of flow = 3km/hr = 300,000/3600 cm/sec. = 83 1/3 cm/sec
Cross-section area of pipe, diameter 20 cm (radius 10cm) = 22/7 x 10² = 314 2/7 cm²
Water flowing in per second = 83 1/3 x 314 2/7 = 26190.476 cm³
Volume of tank = 22/7 x 5² x 200 = 15714 2/7 cm³
Time taken = Volume/Rate = 15714 2/7 ÷ 26190.476 = 0.6 Sec.
∴ It will take 0.6 Sec. to fill the tank.
The time is short because you have put the diameter of the tank to be 10 cm not 10m. If it were 10 m then the volume of the tank would be:
= 22/7 x 500² x 200 = 157142857.1 cm³
And the time taken would be 157142857.1 ÷ 26190.476 sec = 6000 Sec
= 1 hour 40 min.
Thank you.
Cross-section area of pipe, diameter 20 cm (radius 10cm) = 22/7 x 10² = 314 2/7 cm²
Water flowing in per second = 83 1/3 x 314 2/7 = 26190.476 cm³
Volume of tank = 22/7 x 5² x 200 = 15714 2/7 cm³
Time taken = Volume/Rate = 15714 2/7 ÷ 26190.476 = 0.6 Sec.
∴ It will take 0.6 Sec. to fill the tank.
The time is short because you have put the diameter of the tank to be 10 cm not 10m. If it were 10 m then the volume of the tank would be:
= 22/7 x 500² x 200 = 157142857.1 cm³
And the time taken would be 157142857.1 ÷ 26190.476 sec = 6000 Sec
= 1 hour 40 min.
Thank you.
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