a farmer connects a pipe of internal diameter 20 cm from a canal into cylindrical tank which is 8 metre in radius and 4 metre deep water flow through the pipe @ 8 kilometre per hour in how much time will the tank will be filled
Answers
A farmer connects a pipe of internal diameter 20 cm from a canal into a cylindrical tank in his field , which is 10m in diameter and 2 m deep. If water flows through the pipe at the rate of 4km/hr, in how much time will the tank be filled completely.
★Using formula:-
22/7 × 10/2 × 10/2 × 2
1100 / 7 m³
★ Given:-
- Radius of pipe = 10 cm = 0.1 m
- Speed = 4 km/h = 4000m/h
★ Explanation:-
Let length of water column be 'x' meter.
Volume of water column = 1100/7 m³
πr²h
22/7 × 0.1 × 0.1 × x
0.22x / 7
1100 / 7 = 0.22x / 7
1100 = 0.22x
1100 / 0.22 = x
Therefore, length of water column = 5000 m = 5km.
Time = Distance / Speed
Time = 5 / 4
Therefore the time taken to fill the tank completely is 1 hours and 15 minutes.
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AnswEr :
- Radius of Pipe = 20 cm/2 = 10 cm
- Cylindrical Tank Radius = 8 m
- Cylindrical Tank Height = 4 m
- Rate of Water Flow = 8 km/hr
Radius of Pipe = 10 cm = 10/100 m = 1/10 m
Rate of flow of water = 8 km/h = 8000 m/h
Let the time taken be t hr to fill up tank.
• Volume of the water that flows in t hour :
⇒ Area of Cross Section × Speed × Time
⇒ πr² × Speed × Time
⇒ π × ( 1 /10 )² × 8000 × t
⇒ π × 1 /100 × 8000 × t
⇒ π × 80 × t
⇒ 80πt
• Volume of Cylindrical Tank :
⇒ πr²h
⇒ π × ( 8 )² × 4
⇒ π × 64 × 4
⇒ 256π
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• Now we will calculate time taken :
⇝ Vol. of water flows in t hr = Vol. of Tank
⇝ 80πt = 256π
- Dividing Both term by 8π
⇝ 10t = 32 hr
⇝ t = 32 /10 hr
- Changing it into minutes
⇝ t = 32 /10 × 60 minutes
⇝ t = 32 × 6 minutes
⇝ t = 192 minutes
⇝ t = 3 hr. 12 minutes
∴ Time taken will be 3 hr and 12 minutes.