A farmer connects a pipe of internal diameter 20 cm, from a canal into a cylindrical tank in his field, which is 10 m in diameter and 4 m deep. If water flows through the pipe a the rate of 8 km / hour, in how much time will the tank be filled?
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r=10 cm
R=500cm
h=200cm
volume of water flows in 1 hr =pie×10×10×300000(cmcube)
volume of cylindrical tank =pie×500×500×200
time taken to be fill the tank=volume of cylindrical tank÷volume of water flow in 1 hr
=(pie×500×500×200)÷pie×10×10×300000
=(5÷3)hr
=(5÷3)×60
=100min
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