A farmer connects a pipe of internal diameter 20 cm from a canal into a cylindrical tank in her field, which is 10 m in diameter and 2 m deep. If water flows through the pipe at the rate of 3 km/h, in how much time will the tank be filled?
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Answer:
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Answer:
Radius (r1) of circular end of pipe =20020=0.1m
Radius (r1) of circular end of pipe =20020=0.1m⇒Area of cross-section =π×r12=π×(0.1)2=0.01π sq. m
Radius (r1) of circular end of pipe =20020=0.1m⇒Area of cross-section =π×r12=π×(0.1)2=0.01π sq. m⇒Speed of water =3 kilometer per hour = 603000=50 meter per minute.
Radius (r1) of circular end of pipe =20020=0.1m⇒Area of cross-section =π×r12=π×(0.1)2=0.01π sq. m⇒Speed of water =3 kilometer per hour = 603000=50 meter per minute.⇒Volume of water that flows in 1 minute from pipe = 50×0.01π=0.5π cu. m
Radius (r1) of circular end of pipe =20020=0.1m⇒Area of cross-section =π×r12=π×(0.1)2=0.01π sq. m⇒Speed of water =3 kilometer per hour = 603000=50 meter per minute.⇒Volume of water that flows in 1 minute from pipe = 50×0.01π=0.5π cu. m⇒From figure 2, Volume of water that flows in tminutes from pipe = t×0.5π cu. m
Radius (r1) of circular end of pipe =20020=0.1m⇒Area of cross-section =π×r12=π×(0.1)2=0.01π sq. m⇒Speed of water =3 kilometer per hour = 603000=50 meter per minute.⇒Volume of water that flows in 1 minute from pipe = 50×0.01π=0.5π cu. m⇒From figure 2, Volume of water that flows in tminutes from pipe = t×0.5π cu. m⇒Radius (r2) of circular end of cylindrical tank = 210=5 m
Radius (r1) of circular end of pipe =20020=0.1m⇒Area of cross-section =π×r12=π×(0.1)2=0.01π sq. m⇒Speed of water =3 kilometer per hour = 603000=50 meter per minute.⇒Volume of water that flows in 1 minute from pipe = 50×0.01π=0.5π cu. m⇒From figure 2, Volume of water that flows in tminutes from pipe = t×0.5π cu. m⇒Radius (r2) of circular end of cylindrical tank = 210=5 m⇒Depth (h2) of cylindrical tank =2 m
Radius (r1) of circular end of pipe =20020=0.1m⇒Area of cross-section =π×r12=π×(0.1)2=0.01π sq. m⇒Speed of water =3 kilometer per hour = 603000=50 meter per minute.⇒Volume of water that flows in 1 minute from pipe = 50×0.01π=0.5π cu. m⇒From figure 2, Volume of water that flows in tminutes from pipe = t×0.5π cu. m⇒Radius (r2) of circular end of cylindrical tank = 210=5 m⇒Depth (h2) of cylindrical tank =2 m⇒Let the tank be filled completely in t minutes
⇒Volume of water that flows in t minutes from pipe = Volume of water in tank
⇒Volume of water that flows in t minutes from pipe = Volume of water in tankTherefore, t×0.5π=πr22×h2
⇒Volume of water that flows in t minutes from pipe = Volume of water in tankTherefore, t×0.5π=πr22×h2⇒t×0.5=52×2
⇒Volume of water that flows in t minutes from pipe = Volume of water in tankTherefore, t×0.5π=πr22×h2⇒t×0.5=52×2⇒t=0.525×2
⇒Volume of water that flows in t minutes from pipe = Volume of water in tankTherefore, t×0.5π=πr22×h2⇒t×0.5=52×2⇒t=0.525×2⇒t=100