Question

a farmer connects A pipe of internal diameter 25 cm from a Canal into a a cylindrical tank in his field which is 12 metre diameter and 2.5 metre Deep if water flows through the pipe at the rate of 3.6 km per hour in in how much time will take be filled also find the cost of water in the canal departments are at the rate of rupees 0.07 per metre cube​

Answer 1

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Step-by-step explanation:

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Here is your ans....

R = radius of cylinder = 6m

H = height of cylinder = 2.5m

r = radius of pipe = 25/2cm =1/8m

Rate of flow of water = 3.6km/hr

In 1 hr water upto a length of 3.6km = 3600m will come out of pipe.

let the tank be filled in 'x' hrs.

volume of water coming out of pipe in x hrs = volume of cylindrical tank.

(22/7)(1/8)(1/8)(3600)(x) = (22/7)(6)(6)(2.5)

(1/8)(1/8)(3600)( x) = 6 x 6 x 2.5

3600(x) = 36 x 2.5 x 8 x 8

100(x) = 8 x 8 x 2.5

1000(x) = 8 x 8 x 25

x = 16/10 = 1.6 hrs

x = 1 hr.36 min.

Now,

cost of water = volume of cylindrical tank x 0.07

= 22/7 x 6 x 6 x 2.5 x 0.07

= Rs.19.80.

The tank will be filled in 1hr.36 min and the cost of water will be Rs.19.80.

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Step-by-step explanation:

25/2cm is when converted into metre gives 1/8m

pi is taken as 22/7

3.6km/hr is when converted into metre per second gives 3600.

hope it will help you..