Math, asked by Ashishkumarmahapatra, 11 months ago

a farmer for purchasing seeds and fertilizers borrowed a loan from Cooperative Bank after 2 years he paid rupees 5434 and settled the account if the rate of simple interest is 2 whole 1 by 4 what sum did he burrow​

Answers

Answered by BloomingBud
23

\huge{\underline{\underline{\bf SOLUTION :}}}

 

Given :

 

\bf Rate\;\: of\:\: Interest(R) = 2\frac{1}{4}\% \:\:p.a=\frac{9}{4}\% \:\: p.a

\bf Time(T) = 2\:\: years

\bf Amount(A) = Rs\:\:5434

∴ Principal(P) + Simple Interest(S.I) = Rs 5434

\bf \rightarrow P+[\frac{P \times R \times T}{100}]=5434

\bf \rightarrow P+[\frac{P \times 9 \times 2}{4 \times 100}]=5434

\bf \rightarrow P+\frac{9}{200}P=5434

\bf \rightarrow \frac{209}{200}P=5434

\bf \rightarrow P=\frac{5434 \times 200}{209}

\bf P = 5200

Therefore the farmer borrowed Rs 5200 from  bank.

Answered by rajeshrawat2008
7

Answer:

RATE OF INTEREST =9/4%

TIME =2 years

AMOUNT = 5434

principal +simple interest = 5434

p+ (p*R*T/100) =5434

p+ (p*9*2/4*100) = 5434

p + 9/200p =5434

209/200p =5434

p = 5434*200/209

p= 5200

Step-by-step explanation:

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