Question

* A farmer grows vegetables in his field. In 2/3
of the field, he grows potatoes, in 1/4 he grows tomatoes and in the rest of the field, he grows chilli. In what part of the field does he grow chilli?
Pls answer within today it's urgent!!!​

Answer 1

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$\huge \rm \underline{Answer :-}$

Part of field in which potatoes are grown =$\frac{2}{3}$

Part of field in which tomatoes are grown =$\frac{1}{4}$

⇒ Total part of field covered by potatoes and tomatoes =$\frac{2}{3} + \frac{1}{4} =$

$\small\rm{Find \: the \: least \: common \: denominator \: or } \: \green{LCM }\: \rm {of \: the \: two \: denominators} \\\\\rm \green{LCM} \: of \: \red{ 3 } \: and \: \red{ 4 } \: is \:   \green{12} \\\\\rm \small For \: the \: 1st \: fraction, \: since \\\rm \: 3 \: × \: 4 \: = 12, \: \\\rm \: 23  \: = \:   2 \: × \: 43 \: × \: 4  \: = \:  812 \\ \\\rm \small \: Likewise, \: for \: the \: 2nd \: fraction, \: since \\ 4 \: × \: 3 \: = \: 12, \: \\\rm 14 \:  = \:  1 \: × \: 34 \: × \: 3  \: =  \: 312 \\\\\rm \small Add \: the \: two \: fractions :- \\\rm \small 812 \:  + \:  312 \:  = \:  8 \: + \: 312 \:  =  \: 1112 \\\\\rm \small So, \frac{2}{3} + \frac{1}{4}=\frac{11}{12}$

∴ Remaining part of field in which chillies are grown =$1 \: − \: \frac{11}{12 } \: = \frac{1}{12}$

So, Chillies are grown in$\frac{1}{12}$part of field.

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