Question

A farmer had fodder for 40 animals for 60 days. He bought some more animals and the forder lasted for 50 days. How many animals did he buy?​​

Answer 1

Given :-

• No. of Animals = 60
• Fodder was lasted for 40 animals = 60 days

To Find :-

• No. of Animals he had brought & the food lasted for 50 days

Answer :-

According to the Question,

It is given that the fodder for 40 animals was lasted for 60 days .

We have to calculate the no. of animals he had brought in which the fodder lasted for 50 days .

So,

• It is case of direct variation

Let the total animals in 2nd case be x

:⟹ 40/50 = x/60

:⟹ 50 × x = 60 × 40 (direct variation)

:⟹ x = 2400/50

:⟹ x = 48

When farmer had 40 animals the fodder was lasted for 60 days.

If farmer had 48 animals the fodder lasted for 50 days.

So , the Number of animals brought by the farmer = 48-40

:⟹ Number of animals brought by the farmer = 8

So, the farmer brought 8 animals .

Answer 2

$It\: is \: a \: case \: of \: direct \: variation.$

$Let \: the \: total \: number \: of \: animal \: be \: x.$

$\frac{40}{50} = \frac{x}{60}$

$2400 = 50x$

$\frac{2400}{50} = x$

$48 = x$

$Number \: of \: animals \: he \: buy = 48 - 40$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 8$

$Start \: following \: me. \: If \: this \: answer \: is \\ \: helpful \: so \: mark \: my \: answer \: as \\ \: brainliest \: answer.$