Math, asked by sivasubramaniansubra, 8 months ago

A farmer has 49 cows which are numbered from 1 to 49. Cow # 1 gives 1 litre of milk per day, cow # 2 gives 2 litres of milk per day, and like this cow # 49 gives 49 litres of milk per day. The farmer has 7 sons. He wants to give each son 7 cows but the total number of litres of milk given by each set of seven cows must be equal. How would the farmer divide the 49 cows?​

Answers

Answered by dhandapanikeerthi197
0

Given

No. of cows that the farmer have=49

Also given

cow no.(1) gives 1litre of milk and cow no.( 2 )give 2 litre of milk and cow no. (49) gives 49 litre of milk in this way simultaneously for each cow amount of milk given by them is increasing

Then:

total no. of sons that the farmer have=7

Given

no. of cows that the sons will get=7

Also given

The total litres of milk given by the each set of seven cows of the sons should be equal

Consider

Total litre of milk given by that (49)cows =?

Take

by using formula=n(n+1) divided by 2

here

(n) refers to the number where the addition ends

Then

total litre of milk given by that (49)cows =1225

Then

total litre of milk that set of seven cows of each son gives 775 litre of milk per day

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