Question

A farmer has 8000 plants. He wants to plant these in such a way that the number of rows and the number of columns remains same.Find the minimum numbers of plants he need more for this.​

Answer 1

Step-by-step explanation:

8000+x=2,x=2-8000=7998 plants

Answer 2

The minimum number of plants the farmer needs more so, that he can plant these in such a way that the number of rows and the number of columns remains the same is 100.

Step-by-step explanation:

Given,

Number of plants farmer has = $8000$

We have to find the minimum number of plants the farmer needs more for planting.

If the number of rows and number of columns remains the same (equal) then the total number of trees will be in the form of a perfect square (x² )

As $8000$ is not a perfect square, we first need to check for a perfect square above and nearest to $8000$.

Perfect square near $8000$ = $89^{2}$ or $90^{2}$

∴ Square of $89$ is less than $8000$, So we have to take $90$ square

⇒ Plants need = $90^{2} - 8000$

⇒ Plants need = $8100 - 8000$

⇒ Plants need = $100$

Hence, the minimum number of plants the farmer needs more so, that he can plant these in such a way that the number of rows and the number of columns remains the same is 100.

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