a farmer has a rectangular field length of which is two times of it wiedth perimeter of field is 240m find 5he diamence of field
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HEY MATE HERE IS UR ANSWER
LET THE WIDTH OF THE FIELD BE = X
NOW ACCORDING TO QUESTION THE LENGTH IS 2 TIMES THE WIDTH
SO
LENGTH = 2 × X
= 2X
SO NOW WE KNOW THAT THE PERIMETER OF RECTANGLE IS = 2 ( LENGTH + WIDTH ) ---- EQ (1)
ITS GIVEN THAT PERIMETER OF RECTANGLE IS = 240M ---- VALUE (2)
NOW BY EQ - (1) AND VALUE (2) WE HAVE
2( LENGTH + WIDTH ) = 240 M
NOW PUTTING THE VALUE OF LENGHT = 2X AND WIDTH = X WE HAVE
2 ( 2X + X ) = 240M
WHICH IS =
2 ( 3X ) = 240 M
6X = 240 M
SO
X = 240M / 6
THAT IS
X = 40 M
THEREFORE
WIDTH = X = 40 M
AND LENGTH = 2X = 2 × 40 M = 80 M
SO THE DIMENSIONS OF THE FIELD IS 40M × 80M. ( AS DIMENSIONS IS THE LENGTH AND WIDTH
HOPE IT'S HELPFUL IS
⏺️NIPUN ⏺️
BE BRAINLY ☯️
LET THE WIDTH OF THE FIELD BE = X
NOW ACCORDING TO QUESTION THE LENGTH IS 2 TIMES THE WIDTH
SO
LENGTH = 2 × X
= 2X
SO NOW WE KNOW THAT THE PERIMETER OF RECTANGLE IS = 2 ( LENGTH + WIDTH ) ---- EQ (1)
ITS GIVEN THAT PERIMETER OF RECTANGLE IS = 240M ---- VALUE (2)
NOW BY EQ - (1) AND VALUE (2) WE HAVE
2( LENGTH + WIDTH ) = 240 M
NOW PUTTING THE VALUE OF LENGHT = 2X AND WIDTH = X WE HAVE
2 ( 2X + X ) = 240M
WHICH IS =
2 ( 3X ) = 240 M
6X = 240 M
SO
X = 240M / 6
THAT IS
X = 40 M
THEREFORE
WIDTH = X = 40 M
AND LENGTH = 2X = 2 × 40 M = 80 M
SO THE DIMENSIONS OF THE FIELD IS 40M × 80M. ( AS DIMENSIONS IS THE LENGTH AND WIDTH
HOPE IT'S HELPFUL IS
⏺️NIPUN ⏺️
BE BRAINLY ☯️
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