Question

A farmer has enough food to feed 10 animals in his cattle for 6 days. How long the food last if there were 5 more animals in his cattle?​

Answer 1

Answer:

4 days

Step-by-step explanation:

Answer 2

Answer:

4 days

Step-By-Step Explanation:

If the number of animals increases, then it will take fewer days to last.

Then the two quantities are in inverse proportions.

Let the required number of days be p.

$\because x_1y_1 = x_2y_2$

Where,

$x_1 = 10, \: y_1 = 6, \: x_2 = 15$ and $y_2 = p$ (let)

=> 10 × 6 = 15 × p

=> 60 = 15p

=> p = 60/15

=> p = 4

Hence the required number of days = 4.