Question

A farmer has enough food to feed 18 animals in his cattle for 16 days. How long would the food last if 6 animals were sold by him before starting the food ?



Tell...the formula also​

Answer 1

Answer:

A farmer has enough food to feed 18 animals in his cattle for 16 days.

The food would last for 24 days, if 6 animals were sold by him before starting the food.

Apply the concept and formula of Time and Work.

M1*R1*T = M2*R2*T2

$M1*R1*T = M2*R2*T2 \\ 18 \times 16 = (18 - 6) \times t \\ 18 \times 16 = 12 \times t \\ t = 18 \times \frac{16}{12} \\ t = 18 \times \frac{4}{3} = 24 \: days$

Answer 2

Answer:

Correct option is A)

Let the food will now last for x days. Then,

Number of animals 20 30

Number of days 6 x

Clearly, more is the number of animals, less will be the number of days for food to last.

So, it is a case inverse proportion.

∴ 20 × 6 = 30x ⇒ x =

30

20×6

= 4

Hence, the food will now last for 4 days.

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