Question

a farmer has enough food to feed 20 animals for 6 days, how long the food last if there are 10 animals​ in his castle​

Answer 1

$\huge\sf\large\large{Answer :-}$

Let the food will now last for x days. Then,

Number of animals 20 30

Number of days 6 x

Clearly, more is the number of animals, less will be the number of days for food to last.

So, it is a case inverse proportion.

∴ 20 × 6 = 30x ⇒ x = 20×6

3 = 4

Hence, the food will now last for 4 days.

$\huge\sf\large\large{Explanation :-}$

How long would the food last if there were 10 more animals in his cattle? For more number of animals, the food will last less number of days. ∴ It is a case of inverse variation. Therefore, the food will now last for 4 days.