A farmer has enough food to feed 20 animals in hic cattle for 6 days .How long would the food last if there were 10 more animals in his cattle.
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Answered by
6
Hello !
10 + 20 = 30
20 → 6 days
30 → ? days
6 × 30 / 20 = 9 days
Good weekend !
10 + 20 = 30
20 → 6 days
30 → ? days
6 × 30 / 20 = 9 days
Good weekend !
kritikadalal200:
20 animals 6 days. If 10 are added then there are 30 animals. If we will do it by inverse variation then the answer will be 4 days
What's wrong ?
I do not quite understand what is wrong .. I am new and do not speak English very well .. If you could be indulgent, thanks!
Hey! Try to understand if there are 20 animals the food will last for only 6 days if 10 more are added then how food can last for nine days. Food is not increasing only animals are increasing. That's why food will last only for 4 days. You can calculate.
thanks
Je suis désolé d'avoir été méchant avec toi :(
D'accord.
Je m'excuse.
Je dois y aller.
Ok
Answered by
3
For 20 animals food is enough for 6 days.
If 10 more animals are added then there are 30 animals.
Let the number of days the food will last for 30 animals be x.
Animals - Days
20 - 6
30 - x
By inverse variation
x = 20×6÷30
x = 4 days
If 10 more animals are added then there are 30 animals.
Let the number of days the food will last for 30 animals be x.
Animals - Days
20 - 6
30 - x
By inverse variation
x = 20×6÷30
x = 4 days
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