Question

A farmer has enough food to feed 20 animals in his cattle for 6 days, How long the food last if there where 10more animals in his cattle​

Answer 1

Answer:

Number of days are 4

Step-by-step explanation:

Let the number of days be x.

192

Given that he has enough food to feed 20 animals in his cattle for 6 days. Later on, 10 more animals were added.

Therefore the number of days required to feed 30 animals:

20*6 = (20 + 10) * X

120 = 30 * x

x = 120/30

= 4.

Therefore the number of days = 4.

Answer 2

Answer:

4 days

Step-By-Step Explanation:

If the number of animals increases, then it will take fewer days to last.

Then the two quantities are in inverse proportions.

Let the required number of days be p.

$\because x_1y_1 = x_2y_2$

Where,

$x_1 = 20, \: y_1 = 6, \: x_2 = 30$ and $y_2 = p$ (let)

=> 20 × 6 = 30 × p

=> 120 = 30p

=> p = 120/30

=> p = 4

Hence the required number of days = 4.