A farmer has enough food to feed 20 animals in his cattle for 6 days .How long would the there were 10 more animals in his cattle ?
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Answered by
330
Let the number of days be x.
Given that he has enough food to feed 20 animals in his cattle for 6 days.Later on, 10 more animals were added.
Therefore the number of days required to feed 30 animals:
20 * 6 = (20 + 10) * x
120 = 30 * x
x = 120/30
= 4.
Therefore the number of days = 4.
Hope this helps!
Given that he has enough food to feed 20 animals in his cattle for 6 days.Later on, 10 more animals were added.
Therefore the number of days required to feed 30 animals:
20 * 6 = (20 + 10) * x
120 = 30 * x
x = 120/30
= 4.
Therefore the number of days = 4.
Hope this helps!
raviy:
thanks
I am confused. what is the correct answer?
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103
Answer: see the attachment
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