Question

A farmer has enough food to feed 20 animals in his cattle for 6 days. how long would the food last if there were 10 more animals in his cattle?​

Answer 1

Step-by-step explanation:

Let the food will now last for x days. Then,  

Number of animals  20            30

Number of days                      6            x

Clearly, more is the number of animals, less will be the number of days for food to last.  

So, it is a case inverse proportion.

∴ 20 × 6 = 30x ⇒ x =  

30

20×6

​  

 = 4  

Hence, the food will now last for 4 days

Answer 2

Answer:

Here goes the solution!

Let the food will now last for x days. Then,

Number of animals 20 30

Number of days 6 x

Clearly, more is the number of animals, less will be the number of days for food to last.

So, it is a case inverse proportion.

∴ 20 × 6 = 30x ⇒x = (20 × 6)/30 = 4

Hence, the food will now last for 4 days.