Question

A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle ?​

Answer 1

Answer:

Step-by-step explanation:

Let the number of days be=x

Total number of animal= 10 +20= 30

Here the number of animals and days are in inverse proportion

Therefore, 20/30= x/6

x= 6x20/30 =12/3 = 4

Hence, the food will last four days

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Answer 2

Answer:

20 animals =6 days

(20+10) animals =?

30 ×6÷20= 9 days (using cross multiplication method )

Step-by-step explanation:

therefore it will 9 days to feed 30 animals.

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