Question

A farmer has enough food to feed 20 animals in his cattle for 6 days. How long the food last if would there were 25 animals in his cattle?

Answer 1

Answer:

Let the number of days be x

Total number of animals = 20 + 10 = 30

Here the number of animals and the number of days are in inverse proportion.

\therefore\frac{20}{30}=\frac{x}{6}∴

30

20

=

6

x

x=\frac{6\times20}{30}=\frac{12}{3}=4x=

30

6×20

=

3

12

=4

Hence the food will last 4 days.

Answer 2

Answer:

Here,this are in Inverse proportion so 20/25=x/6

25x=20×6. x=120/25=4.8 days