Question

A farmer has enough food to feed 28 animals in his cattle for 9 days.how long would the four last, if there where it more animals in his cattle

Answer 1

Answer:

Answer:

Step-by-step explanation:

No. Of amimals = 28 =28+8=36

No. Of days required=9=x

It is indirect variation

x×y=k

9×36=28x

x=9×36\28

x=7 days

Step-by-step explanation:

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Answer 2

Answer:

7 days

Step-By-Step Explanation:

If the number of animals increases, then it will take fewer days to last.

Then the two quantities are in inverse proportions.

Let the required number of days be p.

$\because x_1y_1 = x_2y_2$

Where,

$x_1 = 28, \: y_1 = 9, \: x_2 = 36$ and $y_2 = p$ (let)

=> 28 × 9 = 36 × p

=> p = 28 × 9/36

=> p = 7

Hence the required number of days = 7.