Question

a farmer has enough food to feed 30 animals in his cattle-fret for 4 day how long would the food last if there were 10 less animal in their farm​

Answer 1

The number of days 20 animals were feed is 6 days

Step-by-step explanation:

Given as :

The number of animals feed for 4 days = 30

i,e number of animals = $A_1$ = 30

numbers of days = $d_1$ = 4

Let The number of days 20 animals were feed = d days

i,e number of animals = $A_2$ = 20

numbers of days = $d_2$ = d

According to question

∵   more animals than less days

So,

animals × food  = constant

i.e  $\dfrac{A_2}{A_1}$  = $\dfrac{d_1}{d_2}$

Or,   $\dfrac{20}{30}$  = $\dfrac{4}{d}$

By cross multiplication

20 ×  d = 30 × 4

or,      d = $\dfrac{30\times 4}{20}$

∴         d = 6

So, The number of days 20 animals were feed = d = 6 days

Hence, The number of days 20 animals were feed is 6 days  Answer