A farmer has enough food to feed 30 animals in his cattle for 8 days. How
long would the food last if there were 10 more animals in his cattle ?
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Step-by-step explanation:
Here the number of animals and the number of days are in inverse proportion.
\therefore\frac{20}{30}=\frac{x}{6}
x=\frac{6\times20}{30}=\frac{12}{3}=4
Hence the food will last 4 days.
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