Math, asked by xTR1GGER, 5 months ago

A farmer has enough food to feed 50 animals in his cattle for 15 days. How long will the food last if there are 25 more animals in his cattle?​

Answers

Answered by 4804250504
1

Answer:

The food will last for 10 days

Step-by-step explanation:

Proportions

The amount of food the farmer needs to feed his animals is proportional to the number of animals and to the number of days they are fed.

This can be written as:

Food=k*N*D

Where k is a constant, N is the number of animals and D is the number of days.

We know that the farmer has enough food to feed N=50 animals for D=15 days, thus:

Food=k*50*15=750k

If the same amount of food is used for 50+25=75 animals, then:

750k=k*75*D

Simplifying:

750=75*D

Dividing by 75:

D=10

Answered by vaibhav1610
1

Step-by-step explanation:

no. of animals (x). x¹ = 50 , y¹ = 50+25 = 75

food will last for (y) x² = 15 , y² = ?

Now let the y² be x

As we know , Inverse proportion = x¹/y¹= x²/y²

Therefore , 50/75 = 15/x

50 × x = 75 × 15

50x = 1125

x = 1125/50

x = 22+1/2

So the food will last in 22 and a half day

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