Question

A farmer has enough good food to feed 25 animals in his cattle for 7 days . How long the foods last if there were 10 more animals in his cattle ?

Answer 1

let some food 25 animal eat in 7 days
then 1 animal eat in 7*25=175
again 35 animal eat=)175/35=5

Answer 2

Answer:

5 days

Step-By-Step Explanation:

If the number of animals increases, then it will take fewer days to last.

Then the two quantities are in inverse proportions.

Let the required number of days be p.

$\because x_1y_1 = x_2y_2$

Where,

$x_1 = 25, \: y_1 = 7, \: x_2 = 35$ and $y_2 = p$ (let)

=> 25 × 7 = 35 × p

=> 175 = 35p

=> p = 175/35

=> p = 5

Hence the required number of days = 5.