A farmer has to go 6 m due to north, 8 m due east and 10 m due upwards to reach his field then what is the displacement from his house to the field?
Answers
Answered by
0
Answer :
A::B::C::D
Solution :
a. Distance travelled = 50+40+20
=110 m
b. [Math Processing Error]AF=AB-BF=AB-DC=50-20=30m His displacement
`AD=sqrt(AF^2+DF^2)
sqrt(30^2+40^2)
=sqrt(2500)=50m

in /_\ED
tantheta = (DE)/(AE)=30-40=3/4
rarr theta = tan^-(-1)(3/4)[Math Processing Error]Hisdisplacementomhishouse→thefieldis50mtan-1 (3/4)` north to east.
Similar questions