A farmer is having a rectangular piece of land measuring 100m×75m. he is doing organic farming in his field according to the demand of the market. For this,he made different square and rectangular shaped pieces of land . The square shaped pieces of land having an area of 625m^2 and 400m^2.
1) he wants to plant cauliflower in the small square piece of land in such a way that the number of plants in each row and column are same. How many plants can he grow in each row and column.
Answers
The perimeter of a rectangular piece of land = 2(Length + Breadth)
= 2(0.7+0.5)
= 2(1.2)
= 2.4 km
\because1km\ =\ 1000m∵1km = 1000m
\therefore0.24\ =\ 1000\times0.24=2400∴0.24 = 1000×0.24=2400 m.
Since 4 rows of wire is required.
\therefore2400\times4=9600∴2400×4=9600 m.
\therefore9600\ m\ =\ 9.6\ km∴9600 m = 9.6 km
Therefore, length of wire required is 9.6 km or 9600 m.
Answer:
Let the length of one side be x metres and the other side be y metres.
Here one side is a compound wall and 30 m wire is used for fencing.
⇒x+y+x=30
⇒y=30−2x
Area of the vegetable garden =100m
2
⇒ xy=100
⇒x(30−2x)=100
⇒30x−2x
2
=100
⇒15x−x
2
=50
⇒x
2
−15x+50=0
⇒x
2
−10x−5x+50=0
⇒(x−10)(x−5)=0
⇒x=5,10
When x=5 we have
y=30−(2×5)=20
When x=10,we have
y=30−(2×10)=10
Hence, the dimensions of the vegetable garden are 5m×20m or 10m×10m