Physics, asked by sewhag, 1 year ago

A farmer is moving along the boundary of a square field of side 20m in 80s. What will be the
magnitude of displacement at the end of 200s. Find the average velocity of the farmer.

Q14. A car is moving along a straight road with uniform acceleration. The following table gives the
speed of the car at various intervals of time:
Time (s) 0 10 20 30 40 50
Speed (m/s) 5 10 15 20 25 30
(a) Plot the speed – time graph for the given data.
(b) Compute the acceleration of the body from the graph.
(c) Find the distance covered by it in first 10s, next 20s and last 10s.

Q15. A body is travelling uniformly with a velocity of 5m/s. Find the distance travelled by the body
graphically in 5s.



pls solve its urgent pls pls
 plz i have a test


sewhag: and acceleration
sewhag: sure
sewhag: ??
sewhag: hey but i think in ques 13 displacement will be 800

Answers

Answered by shariquekhan2500
1
The displacement will be
As the farmer moves 20 meters in 80 seconds it will cross 2 and half side of sqaure but that's the distance the displacement will .
20*20+10*10= x*x
Displacement will be 10√5
Now the average velocity will be the total displacement / total time taken to cover that displacement
The body covers 20 meters in = 80 seconds
Then for covering 10√5 meters it will take 10√5*4 seconds
Now
10√5/10√5*4 gives 1/4 meters per sec
(15) the body will cover 25 meters as the area under the vt graph gives the displacement or the movement that's the motion of the particle

manavjaison: gud
sewhag: solve 14 also
sewhag: pls
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