Chemistry, asked by kanha52291, 1 year ago

A farmer kiss need to straighten a 15% alcohol solution to one of 32% alcohol how much pure alcohol should be added to 400 ml of the 15% solution

Answers

Answered by kajal200612
1

Answer:

100мℓ

400ml has 15% alcohol i.e 60ml .

This means we have 340ml of water or the liquid with which alcohol is mixed 

Let

V be the volume of alcohol added to make the strength 32%

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V/340+V = 32/100. solving this we get V as 160ml

so we need to add 160 -60 = 100ml of alchohol

Explanation:

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Answered by BrainlyRaaz
50

Answer :

  • 100 ml

Step-by-step explanation :

Given :

  • A farmer kiss need to straighten a 15% alcohol solution to one of 32% alcohol.

To find :

  • How much pure alcohol should be added to 400 ml of the 15% solution.

Quantity of pure alcohol in 400 ml of 15 % solution = 400 × 15/100 = 60 ml

Let pure alcohol added to 15 % solution to get 32% solution = x ml.

Then quantity of pure alcohol = (60 + x) ml

According to the given question, we have

60 + x = 32% of (400 + x) = 32/100(400 + x)

⟹ 60 + x = 8/25(400 + x)

⟹ 25(60 + x) = 8(400 + x)

⟹ 1500 + 25x = 3200 + 8x

⟹ 25x - 8x = 3200 - 1500

⟹ 17x = 1700

∴ x = 1700/17 = 100.

Hence, quantity of pure alcohol added to 15 % solution to get 32% solution = 100 ml.

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