a farmer lift a sac of weight of 100kg to a height of 2 m. find work done. with explanation
Answers
Answered by
1
Answer:
w=mgh=100×9.8×2=1960j
This work is done against gravitational field (g=9.8m/s²)
Answered by
4
Answer:
M = 100 kg
h = 2 m
Work done against gravitational force,
W = mgh
= 100 x 9.8 x 2
= 196 J
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