a farmer loses 10% by selling a cow for ₹7200. At what price should he have sold it to make a profit of 15%?
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Answer:
Cost price of buffalo =Rs.44000
Loss of 5%
∴Loss=
100
5
×44000=2200
Selling price of buffalo =Rs.44000−2200=Rs. 41800
Cost price of cow =Rs.18000
Profit of 10%
Hence,
profit=
100
10
×18000=1800
So, Price=18000+1800=Rs. 19800
Cost price of both cow and buffalo
=44000+18000=Rs. 62000
Selling price of both cow and buffalo
⇒Rs.(19800+41800)=Rs.61600
∴Loss=62000−61600=Rs.400
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