A farmer move along the boundary of a Square field of side lom in 40s. What will be the magnitude of displacement of the farmer at the end of 2 minutes. 20 Seconds ?
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bro this is physic
I don't know the phy
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Total distance covered 10m in 40sec
Total time taken= 2min 20sec= 140sec
Total round completed = 140/40=3.5 rounds
So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.
AC2= AB2 +BC2
AC2= (10)2 +(10)2
AC2= 100+100
AC2=200
AC = (200)1/2
AC= 10× (2) ½
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