Question

a farmer moves a boundary of a square field of side 20m in 40s. what will be the magnitude of displacement and distance of the farmer at the end of 2mjns 20secs.

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Answer 1

20m in 40s

LET THE DISTANCE BE x meters

20m in 40s

x m in 2 min 20 sec=140 sec

x=20×140/40

x=70m

THEREFORE,DISTANCE TRAVELLED IS 70m.

NOW THE TOTAL PERIMETER OF SQUARE IS 20×4=80m

GIVEN,

HE TRAVELS 20m in 40sec

SO HE TRAVELS TOTAL 80m in 160 sec,IF HE TRAVELS ALL THOSE 80m AGAIN HE REACHES STARTING POINT AT THAT TIME THE DISPLACEMENT WILL BE ZERO.

BUT THEY ASKED DISPLACEMENT AT THE END OF 2min 20sec.

SO FIRST WE HAVE TO CALCULATE THE DISTANCE TRAVELLED IN 2min 20sec WHICH WE ALREADY SOLVED AND SUBTRACT IT FROM 80m.

DISPLACEMENT=80-70m=10m

WE SUBTRACTED 70 FROM 80 AS WE KNOW TAHT DISTANCE TRAVELLED BY HIM 70m AND WE FROM 80 AS DISPLACEMENT MEANS THE SHORTEST DISTANCE FROM THE STARTING POINT.

SO WE ARE SUBTRACTING 70 FROM 80.