Question

A farmer moves along a boundary of a square field 10m in 40sec. What will be the magnitude of displacement
of the farmer at the end of 2 min 20 sec from his initial position ?​

Answer 1

Let the Initial position of farmer be P

So, The distance covered by the farmer in 40 Sec = 4 × 10 = 40 m

Since, In 40 Sec farmer move 40m

Thus , In 140sec ( 2min 20sec) Farmer will move 140m.