a farmer moves along a boundary of a square field of side 10m in 40 sec. what will be the magnitude of the farmer in the end of 2 minutes 20 seconds
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Answered by
2
Answer:
35
Explanation:
Given, in 40 secs, the farmer moved=10m
40secs, =40/60=2/3minutes
So, in 1minute, the farmer moves, = 10 * 3/2
=15m
2 minutes 20seconds = 7/30minutes.
Therefore, the magnitude of the farmer at the end of 2 minutes 20 seconds,
=15 * 7/3
=5 * 7
=35m
Answered by
0
Answer:
35m
Explanation:
Here a farmer can walk 35m in given time 2.2min
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