Science, asked by shubh9878, 9 months ago

a farmer moves along a boundary of a square field of side 10m in 40 sec. what will be the magnitude of the farmer in the end of 2 minutes 20 seconds​

Answers

Answered by donskvdas
2

Answer:

35

Explanation:

Given, in 40 secs, the farmer moved=10m

40secs, =40/60=2/3minutes

So, in 1minute, the farmer moves, = 10 * 3/2

=15m

2 minutes 20seconds = 7/30minutes.

Therefore, the magnitude of the farmer at the end of 2 minutes 20 seconds,

=15 * 7/3

=5 * 7

=35m

Answered by alesharath1234
0

Answer:

35m

Explanation:

Here a farmer can walk 35m in given time 2.2min

Attachments:
Similar questions