Question

a farmer moves along a boundary of a square field of side 10m in 40 sec. what will be the magnitude of displament of the farmer at the end of 2 minutes 20 seconds​
from its start..... please explain ​

Answer 1

$\bold\red{\underline{\underline{Answer:}}}$

Displacement will be 5m.

$\bold\orange{Given:}$

Side of square=10 m

Time he takes to cover one side =40sec

$\bold\pink{To \ find:}$

Displacement after 2 minute 20 seconds.

$\bold\green{\underline{\underline{Solution}}}$

2 minute 20 seconds=140 seconds

Hence he will cover 3 sides in 120 seconds

and in remaining 20 seconds he will cover half of fourth side.

Distance cover in 2mins 20sec=35m

Displacement is minimum distance between starting and ending points.

Whole perimeter of square=40 metre.

Distance cover is 2mins 20sec

=35 metre

Displacement is

40-35=5