A farmer moves along a boundary of square field of side 10 m in 40 seconds.what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?
Answers
Answer:
Hi friend,
Total distance covered 10m in 40sec
Total time taken= 2min 20sec= 140sec
Total round completed = 140/40=3.5 rounds
So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.
AC2= AB2 +BC2
AC2= (10)2 +(10)2
AC2= 100+100
AC2=200
AC = (200)1/2
AC= 10× (2) ½
Hope it helps......
Question:
A farmer moves along a boundary of square field of side 10 m in 40 seconds.what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?
Answer:
Total distance covered in 10 m in 40 second.
Total time taken = 2 minute 20 second = 140 second.
Total round completed = 140 ÷ 40 = 3.5 second.
So,if an object moves from A to D,the shortest path will be form A to C.So,displacement is AC,that we will find by Pythagoras Theorem.
AC²=AB²+BC²
AC²=(10)²+(10)²
AC²=100+100
AC²=200
AC= (200)½
AC=10×2½