Question

A farmer moves along a boundry in a square field of side 10m in 40 seceonds. what will be tge magnitude of displacement of farmer in 2 minutes 20 seconds

Answer 1

Hey there!

Given that,
Side of the square field = 10m

∴ Perimeter of the square field = 10×4 = 40m

2min + 20s = 120+20
= 140s

Displacement after 140s =

In 40s famer moves 40m,

So, distance covered in 1 sec = 40/40 = 1m

∴ In 140s = 140×1 = 140m

No.of rotation to cover 140m
= 140/40
= 3.5 rounds.

Thus, after 3.5 rounds, he will be at the point C

∴ Displacement (AC) =

$\sqrt{(10m {}^{2}) + (10m {}^{2}) }$

$\sqrt{200m {}^{2} }$

$10 \sqrt{2}$

So, Displacement of the farmer = 10 √2 m or 14.14 m



Glad if helped :D