Question

a farmer moves along a boundry of a squre field of side 10metre in 40 seconds what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his intial position??​

Answer 1

Answer:

Total distance covered 10m in 40sec

Total time taken= 2min 20sec= 140sec

Total round completed = 140/40=3.5 rounds

So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.

AC2= AB2 +BC2

AC2= (10)2 +(10)2

AC2= 100+100

AC2=200

AC = (200)1/2

AC= 10× (2) ½

Explanation :

$\bold\pink{plz follow me and barainlist also dear friend plz }$