Question

A farmer moves along boundary of a square field of side 10m in 40 seconds what will be the magnitude of displace of farmer at the end of 2 minutes 20 seconds from his initial positions

Answer 1

Answer:

the answer is 35 metres.

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Answer 2

Answer:

The displacement of the farmer from the initial position is 5 metres.

Explanation:

STEPS:

Let the four vertices of the square be a,b,c,d.

I AM GOING TO WRITE THE ANSWER WITH RESPECT TO EACH SIDE.

Side AB:

length = 10m

time = 40s

So when he reach C 1min 20s will be over. And is displacement at that point will be 10√2.

When he reach D the displacement will be 10m

and there will be a remaining 20s. During that time he will cover half distance of a side.

So the final displacement in the side CD will be :

10-5= 5m

Thus the displacement will be 5m.

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