Question

A farmer moves along the boundaries of a square field of side 10m in 40 s . What will be the magnitude of displacement of farmer at ebd of 2min 20 s from initial position

Answer 1

ANSWET

10 root 2

Step-by-step explanation:

2min and 20sec = 140 sec

If he covers 10 m in 40 sec = one round , then he will cover 3.5 rounds in 140 sec (140/40)

So , in 3 rounds the displacement will be zero and in 0.5 rounds it will be (100 + 100) raise to the power 1/2

Hope it helps