a farmer moves along the boundary of a sqare field of side 10m in 40s.what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?
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After 140 seconds the farmer will complete 140/40=3 and 1/2 rounds. So he/she will be at the diagonally opposite corner.
Displacement = * sqrt2 in the direction of the diagonal.
Displacement = * sqrt2 in the direction of the diagonal.
kvnmurty:
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