A farmer moves along the boundary of a square feild of side 10 meter in 40 sec. what will be the magnitude of displacement of the farmer at the end of 2 minute 20 second from his initial position.
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total time =140seconds
first we have to find the distance covered
140/40=3.5meters
then for finding AC our displacement
we use hypoteneous
(AC)^2=(AB)^2+(BC)^2
(AC)^2=10^2+10^2
(AC)^2=100+100
(AC)^2=200
AC=√200
AC=√100×2
AC=10√2
so the displacement made by farmer is 10√2
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