Physics, asked by janhavialone31, 3 months ago

a farmer moves along the boundary of a square feild of side 10 m in 40 seconds. what will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position​

Answers

Answered by soumyanshushekhar
4

Answer:

In 40 sec he moves = 10m

In 2min 20 sec (140sec) he will move = 10×140/40 = 35m

So by moving 35m he will be in 5m forwards from 3rd side and the displacement will be = 10-5 = 5m from origin and 90° from previous displacement direction

Thus, displacement will be 5m

hope this will help you

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