Question

A farmer moves along the boundary of a square field of 10m in 40s what will be the magnitude of farmer at the end of 2 min and 20 second form his initial position......


the person who willl answer 1st I will mark as brainliest........​

Answer 1

Solution :

First of all convert the given time 2 minutes 20 seconds into seconds.

Total Time = 2 minutes 20 seconds

→ 2 × 60 seconds + 20 seconds

→ 120 seconds + 20 seconds

→ 140 seconds

Now,

In 40 seconds,Round made = 1

So,

In 140 seconds = 3.5 rounds

Thus,the farmer will make three and half rounds of the square field. If the farmer starts from position A,then after completion of 3 rounds, he'll be at starting position A. But in the next half round,Farmer will move from A to B,and B to C,so that his final position will be at C. Thus,the net displacement of farmer will be AC. Now ABC is a right angled triangle in which AC is the hypotenuse.

[Refer to the attachment]

So,

Using Pythagoras Theorem :

★ (AC)² = (AB)² + (BC)²

→ (AC)² = (10)² + (10)²

→ (AC)² = 100 + 100

→ (AC)² = 200

→ AC = √200

→ AC = 14.143 m

$\therefore$ The magnitude of the displacement of the farmer at the end of 2 minutes 20 seconds will be 14.143 metres