Physics, asked by happy666, 9 months ago

a farmer moves along the boundary of a square field of side 10m in 40 second .what will be the magnitude of the displacement of the farmer at the end of 2min and 20 second​

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Answered by Anonymous
3

Answer: 5 metres

Explanation:

The farmer moves 10 metre in 40 seconds so in 140 seconds he will move 35 metres:- 140÷40=3.5

So whatever he was doing in 40 seconds will be multiplied by 3.5

So 3.5×10=35 metres

Let's suppose he started from point 'c' so he will be 5 meters away from the starting point after he has walked 35 metres

So the displacement will be 5 metres

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