a farmer moves along the boundary of a square field of side 10 metre in 40 second what will be the magnitude of displacement of the farmer and of 2 minutes 20 seconds from his initial position
Answers
Answer:
Hi friend,
Total distance covered 10m in 40sec
Total time taken= 2min 20sec= 140sec
Total round completed = 140/40=3.5 rounds
So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.
AC2= AB2 +BC2
AC2= (10)2 +(10)2
AC2= 100+100
AC2=200
AC = (200)1/2
AC= 10× (2) ½
Hope it helps
Answer:
Explanation:
The farmer covers boundary of square field I. E. 10x4=40m in 40s
So he covers distance in 2m 20s I. E.
140s =1m x140s (40m=40m ::::1s=1m)
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Perimeter of square is 40m so in 140m he covers 3 complete rounds and comes to opposite corner from where he starts
And then we find the lengthat of the diagonal of the square ....
BY PYTHAGOROUS THEOREM
Diagonal^2=10^2+10^2
===underfoot of 200 = newer
Answer