Math, asked by SakshiGouniyal, 1 year ago

A farmer moves along the boundary of a square field of side 10 m in 40 seconds . What will be the magnitude of displacement of the farmer at the end of 2m 20sec from his initial position

Answers

Answered by BRAINLYY
1
Converting 2 min 20 sec ====> 140 sec

He completes 1 round in 40 sec therefore he will complete 3 and half round
after 140 sec.

half round means 2 sides
Displacement will be equal to hypotenuse of the square

= √10^2 + 10^2
= √ 200

ANSWER = √200 m

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MARK AS BRAINLIEST
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